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-.4x^2+3.2x+5.6=0
We add all the numbers together, and all the variables
-0.4x^2+3.2x+5.6=0
a = -0.4; b = 3.2; c = +5.6;
Δ = b2-4ac
Δ = 3.22-4·(-0.4)·5.6
Δ = 19.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{19.2}}{2*-0.4}=\frac{-3.2-\sqrt{19.2}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{19.2}}{2*-0.4}=\frac{-3.2+\sqrt{19.2}}{-0.8} $
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